做网站的一般要多钱做竞价托管的公司

力扣题-11.24

[力扣刷题攻略] Re：从零开始的力扣刷题生活

力扣题1：151. 翻转字符串里的单词

解题思想：保存字符串中的单词即可

class Solution(object):def reverseWords(self, s):""":type s: str:rtype: str"""word_list = s.split()result = ""for i in range(len(word_list)-1,-1,-1):if i != 0 :result += word_list[i]+" "else:result += word_list[i]return result

class Solution {
public:string reverseWords(string s) {vector<string> wordList = splitWords(s);string result = "";for (int i = wordList.size() - 1; i >= 0; --i) {if (i != 0) {result += wordList[i] + " ";} else {result += wordList[i];}}return result;}private:vector<string> splitWords(string s) {vector<string> words;istringstream iss(s);string word;while (iss >> word) {words.push_back(word);}return words;}
};