排序的方式

排序的稳定性

• 什么是排序的稳定性？
  不改变相同数据的相对顺序

• 排序的稳定性有什么意义？

  • 假定一个场景：
    一组成绩：100，88，98，98，78，100（按交卷顺序排列，先交在前）
    先需要对这组数据按降序排列，如果分数相同，先交卷的排在前面。

在以上这种场景下，选择具有稳定性的排序方式就很有必要。

排序方式分析比较汇总

912.排序数组 - 力扣（LeetCode）

👉题目链接

/*** Note: The returned array must be malloced, assume caller calls free().*///栈
// 支持动态增长的栈
typedef int STDataType;
typedef struct Stack
{STDataType* _a;int _top;		// 栈顶int _capacity;  // 容量 
}Stack;
// 初始化栈 
void StackInit(Stack* ps)
{STDataType* tmp = (STDataType*)malloc(4 * sizeof(STDataType));if (!tmp){perror("malloc fail");exit(-1);}ps->_a = tmp;ps->_top = 0;ps->_capacity = 4;
}
// 入栈 
void StackPush(Stack* ps, STDataType data)
{assert(ps);if (ps->_capacity == ps->_top){STDataType* tmp = (STDataType*)realloc(ps->_a, 2 * ps->_capacity * sizeof(STDataType));if (!tmp){perror("realloc fail");exit(-1);}ps->_a = tmp;ps->_capacity *= 2;}ps->_a[ps->_top] = data;ps->_top++;
}
// 出栈 
void StackPop(Stack* ps)
{assert(ps);assert(!StackEmpty(ps));assert(ps->_top);ps->_top--;}
// 获取栈顶元素 
STDataType StackTop(Stack* ps)
{assert(ps);assert(ps->_top);return ps->_a[ps->_top - 1];
}
// 获取栈中有效元素个数 
int StackSize(Stack* ps)
{assert(ps);return ps->_top;
}
// 检测栈是否为空，如果为空返回非零结果，如果不为空返回0 
int StackEmpty(Stack* ps)
{assert(ps);return ps->_top == 0;
}
// 销毁栈 
void StackDestroy(Stack* ps)
{assert(ps);free(ps->_a);ps->_capacity = ps->_top = 0;ps->_a = NULL;
}//插入排序
void InsertSort(int* a, int n)
{assert(a);for (int i = 1; i < n; i++){int tmp = a[i];int end = i - 1;while (end >= 0){if (a[end] <= tmp){break;}//a[end + 1] = a[end--];???为什么错误a[end + 1] = a[end];end--;}a[end + 1] = tmp;}}// 希尔排序
void ShellSort(int* a, int n)
{assert(a);int gap = n / 2;while (gap){for (int i = 1; i < n; i++){int tmp = a[i];int end = i - gap;while (end >= 0){if (a[end] <= tmp){break;}a[end + gap] = a[end];end -= gap;}a[end + gap] = tmp;}gap /= 2;}
}void Swap(int* x, int* y)
{assert(x && y);int tmp = *x;*x = *y;*y = tmp;
}// 选择排序
void SelectSort(int* a, int n)
{assert(a);int begin = 0, end = n - 1;while (begin < end){int mini = begin, maxi = end;//[begin+1,end-1]for (int j = begin; j <= end; j++){if (a[j] < a[mini])mini = j;if (a[j] > a[maxi])maxi = j;}//swap之前 min==a[mini]  max==a[maxi]Swap(&a[begin], &a[mini]);//swap之后:begin → min ; mini → original-a[begin]//if(original-a[begin] → max)则会影响 a[maxi] =? maxif (begin == maxi)//如果原本begin指向的数是max，则swap之后这个数已经被交换到了mini所指向的位置maxi = mini;Swap(&a[end], &a[maxi]);++begin;--end;}
}// 堆排序
void AdjustDwon(int* a, int n, int root)
{assert(a);int parent = root;int child = parent * 2 + 1;while (child < n){if ((child + 1) < n && a[child + 1] > a[child])++child;if (a[parent] < a[child])Swap(&a[parent], &a[child]);elsebreak;parent = child;child = parent * 2 + 1;}
}
void HeapSort(int* a, int n)
{assert(a);//建大堆for (int parent = (n - 1 - 1) / 2; parent >= 0; parent--){AdjustDwon(a, n, parent);}int end = n - 1;while (end){Swap(&a[0], &a[end]);AdjustDwon(a, end, 0);end--;}
}
// 冒泡排序
void BubbleSort(int* a, int n)
{assert(a);for (int j = 0; j < n; j++){for (int i = 0; i < n - j - 1; i++){if (a[i] > a[i + 1])Swap(&a[i], &a[i + 1]);}}
}// 快速排序递归实现
// 三数取中
int GetMidIndex(int* a, int left, int right)
{int begin = left, end = right;int middle = (left + right) / 2;if (a[begin] < a[end]){if (a[middle] < a[begin])return begin;else if (a[middle] > a[end])return end;elsereturn middle;}else{if (a[middle] < a[end])return end;else if (a[middle] > a[begin])return begin;elsereturn middle;}}
// 快速排序hoare版本
int hoareSort1(int* a, int left, int right)
{assert(a);if (left >= right)return;// if ((right - left + 1) < 5)// {// 	InsertSort(a + left, right - left + 1);// }else{int key = left, begin = left, end = right;int mid = GetMidIndex(a, left, right);Swap(&a[mid], &a[key]);while (left < right){while (left < right && a[right] >= a[key]){--right;}while (left < right && a[left] <= a[key]){++left;}Swap(&a[left], &a[right]);}Swap(&a[key], &a[right]);//left==right//[begin,left-1] [right+1,end]hoareSort1(a, begin, left - 1);hoareSort1(a, right + 1, end);}return right;
}// 快速排序挖坑法
int HoleSort2(int* a, int left, int right)
{if (left >= right)return;int key = a[left];int hole = left, begin = left, end = right;while (left < right){while (left < right && a[right] >= key){--right;}a[hole] = a[right];hole = right;while (left < right && a[left] <= key){++left;}a[hole] = a[left];hole = left;}a[right] = key;//[begin,left-1] [right+1,end]HoleSort2(a, begin, left - 1);HoleSort2(a, right + 1, end);return right;
}// 快速排序前后指针法
int PointSort3(int* a, int left, int right)
{assert(a);if (left >= right)return;int keyi = left;int prev = left, cur = left;while (cur <= right){if (a[cur] < a[keyi] && cur != prev)Swap(&a[++prev], &a[cur]);++cur;}Swap(&a[keyi], &a[prev]);//[left,prev-1][prev+1,right]PointSort3(a, left, prev - 1);PointSort3(a, prev + 1, right);return prev;
}// 快速排序 非递归实现
void QuickSort(int* a, int left, int right)
{assert(a);Stack st;StackInit(&st);StackPush(&st, left);StackPush(&st, right);while (!StackEmpty(&st)){int end = StackTop(&st);StackPop(&st);int begin = StackTop(&st);StackPop(&st);int keyi = hoareSort1(a, begin, end);//[begin,keyi-1] keyi [keyi+1,end]if (keyi + 1 < end){StackPush(&st, keyi + 1);StackPush(&st, end);}if (begin < keyi - 1){StackPush(&st, begin);StackPush(&st, keyi - 1);}}StackDestroy(&st);
}
// 归并排序递归实现
void _MergeSort(int* a, int left, int right, int* tmp)
{assert(a && tmp);if (left == right)return;int middle = (left + right) / 2;//[left,  middle] [middle+1,right]//[begin1,end1]   [begin2,end2]int begin1 = left, end1 = middle, begin2 = middle + 1, end2 = right;//递归分解_MergeSort(a, begin1, end1, tmp);_MergeSort(a, begin2, end2, tmp);//mergeint i = begin1;while (begin1 <= end1 && begin2 <= end2){if (a[begin1] <= a[begin2]){tmp[i++] = a[begin1++];}else{tmp[i++] = a[begin2++];}}while (begin1 <= end1){tmp[i++] = a[begin1++];}while (begin2 <= end2){tmp[i++] = a[begin2++];}memcpy(a + left, tmp + left, sizeof(int) * (right - left + 1));
}
void MergeSort(int* a, int n)
{assert(a);int* tmp = (int*)malloc(sizeof(int) * n);if (!tmp){perror("malloc fail");exit(-1);}_MergeSort(a, 0, n - 1, tmp);free(tmp);tmp = NULL;
}// 归并排序非递归实现
void MergeSortNonR(int* a, int n)
{assert(a);int* tmp = (int*)malloc(sizeof(int) * n);if (!tmp){perror("malloc fail");exit(-1);}int range = 1;while (range < n){for (int i = 0; i < n; i += 2 * range){int begin1 = i, end1 = i + range - 1;int begin2 = i + range, end2 = i + 2 * range - 1;int j = begin1;//越界//end1越界if (end1 >= n){end1 = n - 1;begin2 = end2 + 1;//begin2 > end2;}else if (begin2 == n){begin2 = end2 + 1;//begin2 > end2;}else if (end2 >= n){end2 = n - 1;}//mergewhile (begin1 <= end1 && begin2 <= end2){if (a[begin1] <= a[begin2]){tmp[j++] = a[begin1++];}else{tmp[j++] = a[begin2++];}}while (begin1 <= end1){tmp[j++] = a[begin1++];}while (begin2 <= end2){tmp[j++] = a[begin2++];}}memcpy(a, tmp, sizeof(int)*n);range *= 2;}free(tmp);tmp = NULL;
}// 计数排序
void CountSort(int* a, int n)
{assert(a);int min = a[0], max = a[0];for (size_t i = 0; i < n; i++){if (a[i] > max)max = a[i];if (a[i] < min)min = a[i];}int size = max - min + 1;int* tmp = (int*)calloc(size, sizeof(int));if (!tmp){perror("calloc fail");exit(-1);}//计数for (size_t i = 0; i < n; i++){++tmp[*(a + i) - min];}int j = 0;for (size_t i = 0; i < size; i++){while (tmp[i]--){a[j++] = i + min;}}free(tmp);tmp = NULL;
}int* sortArray(int* nums, int numsSize, int* returnSize){*returnSize=numsSize;//InsertSort(nums,numsSize);//超出时间限制//ShellSort(nums,numsSize);//SelectSort(nums,numsSize);//超出时间限制//HeapSort(nums,numsSize);//BubbleSort(nums,numsSize);//超出时间限制//hoareSort1(nums,0,numsSize-1);//对于大量重复数据，超出时间限制//HoleSort2(nums,0,numsSize-1);//超出时间限制//PointSort3(nums,0,numsSize-1);//对于大量有序数据，超出时间限制//QuickSort(nums,0,numsSize-1);//对于大量重复数据，超出时间限制//MergeSort(nums,numsSize);//MergeSortNonR(nums,numsSize);//CountSort(nums,numsSize);return nums;
}