免费ppt模板大全下载的网站,请人做网站需要多少钱,网站开发公司凭证,网站图片设计效果图前言 SimpleCG的使用方法在前面已经介绍了许多#xff0c;有兴趣的同学如果有去动手#xff0c;制作一些简单动画应该没多大问题的。所以这次我们来演示一下简单动画。我们刚学习C语言的递归函数时#xff0c;有一个经典例子相信很多同学都写过#xff0c;那就是汉诺塔。那…前言 SimpleCG的使用方法在前面已经介绍了许多有兴趣的同学如果有去动手制作一些简单动画应该没多大问题的。所以这次我们来演示一下简单动画。我们刚学习C语言的递归函数时有一个经典例子相信很多同学都写过那就是汉诺塔。那么我们今天就来写一个汉诺塔的直观动画演示。
运行程序下载bin/AnimateHannuo.zip · master · b2b160 / SimpleCG_Demo · GitCode
一、全部源码 #include ../import/include/CGBoard.h
#include math.h
#ifdef _DEBUG
#pragma comment(lib,../import/lib/SimpleCG_MDd.lib)
#else
#pragma comment(lib,../import/lib/SimpleCG_MT.lib)
#endif#define C_FLOOR_CNT 7
#define C_FLOOR_BOTTOM 380
#define C_HAN_HEIGHT 10
#define C_HAN_SPEED 30int g_nWidth 640; //画面宽度
int g_nHeight 400; //画面高度
enum ENUM_DIRECTION
{enumDIR_NULL,enumDIR_UP,enumDIR_DOWN
};
struct tagHannuo
{int nNumber;COLORREF nColor;int nWidth;int nPosHan;int nDir;POINT ptPos;
};tagHannuo g_pHannuo[C_FLOOR_CNT];
int g_nMoving -1;
void DrawHan()
{int i;int j0;setlinewidth(2);for(i0;i3; i ){_line( 100 200 * i, 50, 100 200 * i,C_FLOOR_BOTTOM );_line( 20 200 * i, C_FLOOR_BOTTOM, 180 200 * i,C_FLOOR_BOTTOM );}int nIndex 0;for(j0;j3;j){nIndex 0;for(iC_FLOOR_CNT-1;i0; i-- ){if(g_pHannuo[i].nPosHan j i ! g_nMoving){setfillcolor(g_pHannuo[i].nColor);_solidrectangle( 100 200 * g_pHannuo[i].nPosHan - g_pHannuo[i].nWidth/2, C_FLOOR_BOTTOM - nIndex * C_HAN_HEIGHT - C_HAN_HEIGHT, 100 200 * g_pHannuo[i].nPosHan g_pHannuo[i].nWidth/2, C_FLOOR_BOTTOM - nIndex * C_HAN_HEIGHT);nIndex;}}}
}
void DrawMoving()
{if(g_nMoving0){setfillcolor(g_pHannuo[g_nMoving].nColor);_solidrectangle( g_pHannuo[g_nMoving].ptPos.x, g_pHannuo[g_nMoving].ptPos.y, g_pHannuo[g_nMoving].ptPos.x g_pHannuo[g_nMoving].nWidth, g_pHannuo[g_nMoving].ptPos.y C_HAN_HEIGHT);}
}
void DrawAll()
{ClearDevice();DrawHan();DrawMoving();ReflushWindow();
}
void Moving( int nItem, int nFrom, int nTo )
{g_nMoving nItem;g_pHannuo[nItem].ptPos.x 100 200 * nFrom - g_pHannuo[nItem].nWidth/2;for( g_pHannuo[nItem].ptPos.y C_FLOOR_BOTTOM - C_FLOOR_CNT * C_HAN_HEIGHT; IsShowingWindow()g_pHannuo[nItem].ptPos.y40; g_pHannuo[nItem].ptPos.y-10 ){DrawAll();Sleep(C_HAN_SPEED);}int nXStep (nTo - nFrom) * 5;int nDest 100 200 * nTo - g_pHannuo[nItem].nWidth/2;for( g_pHannuo[nItem].ptPos.x 100 200 * nFrom - g_pHannuo[nItem].nWidth/2; IsShowingWindow()abs(g_pHannuo[nItem].ptPos.x-nDest)5; g_pHannuo[nItem].ptPos.xnXStep ){DrawAll();Sleep(C_HAN_SPEED);}g_pHannuo[nItem].ptPos.x 100 200 * nTo - g_pHannuo[nItem].nWidth/2;for( g_pHannuo[nItem].ptPos.y 40; IsShowingWindow()g_pHannuo[nItem].ptPos.yC_FLOOR_BOTTOM - C_FLOOR_CNT * C_HAN_HEIGHT; g_pHannuo[nItem].ptPos.y10 ){DrawAll();Sleep(C_HAN_SPEED);}g_nMoving -1;g_pHannuo[nItem].nPosHan nTo;
}
void MoveHan( int nFloor, int nFrom, int nTo, int nMiddle )
{if( nFloor 1 ){Moving( nFloor-1, nFrom-1, nTo-1);return;}MoveHan( nFloor-1, nFrom, nMiddle, nTo );Moving( nFloor-1, nFrom-1, nTo-1);MoveHan( nFloor-1, nMiddle, nTo, nFrom );
}
void DrawProcess()
{bool bIsRunning true;int i;srand(GetTickCount());for(i0;iC_FLOOR_CNT; i ){g_pHannuo[i].nNumberi1;g_pHannuo[i].nColor RGB(rand()%200,rand()%200,rand()%200);g_pHannuo[i].nDir enumDIR_NULL;g_pHannuo[i].nPosHan 0;g_pHannuo[i].nWidth 20*(i1);}MoveHan(C_FLOOR_CNT,1,2,3);DrawAll();
}
int _tmain(int argc, _TCHAR* argv[])
{//初始化if( !ShowingBoard(g_nWidth,g_nHeight, DrawProcess))return 1;//关闭图库CloseBoard();return 0;
}对于写过汉诺塔的同学来说程序逻辑应该没什么难度就是在递归程序上增加了动画过程。
二、演示效果 对于5层来说是不难的但递归对于层数增加所带来的时间消耗是呈指数增加的所以通过动画来观察层数增加带来的时间消耗非常直观。在原始的汉诺塔里是64层要移完所有的层数将会世界末日因为即便到世界的尽头也无法完成。有兴趣的同学可以把代码输入并把层数加大看看。
三、代码下载
汉诺塔演示源代码
AnimateHannuo · master · b2b160 / SimpleCG_Demo · GitCode
库安装方法如下
SimpleCG库安装使用_b2b160的博客-CSDN博客
