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news2023/5/27 7:14:
目录
一、得出三角形的三个角点二、用类似尺规作图法得出三角形圆心 1、以三角形三角点画出圆形轮廓2、求出三角形轮廓与圆形轮廓之间的交点3、获得角平分线#xff0c;三边角平分线交点为圆心三、求出圆心到边最短距离即半径 …Halcon得出三角形内切圆
news2023/5/27 7:14:
目录
一、得出三角形的三个角点二、用类似尺规作图法得出三角形圆心 1、以三角形三角点画出圆形轮廓2、求出三角形轮廓与圆形轮廓之间的交点3、获得角平分线三边角平分线交点为圆心三、求出圆心到边最短距离即半径 一、得出三角形的三个角点
参考上篇文章“Halcon提取三角形边缘以及获取角点”
二、用类似尺规作图法得出三角形圆心
以三角形三个边为圆心生成三个圆形轮廓 求出轮廓与轮廓之间的交点 再以交点为圆心画圆轮廓得到两个圆的交点获得角平分线三边角平分线交点为圆心
1、以三角形三角点画出圆形轮廓
gen_circle_contour_xld (ContCircle1, RowA, ColumnA, 20, 0, 6.28318, positive, 1)
gen_circle_contour_xld (ContCircle2, RowB, ColumnB, 20, 0, 6.28318, positive, 1)
gen_circle_contour_xld (ContCircle3, RowC, ColumnC, 20, 0, 6.28318, positive, 1)2、求出三角形轮廓与圆形轮廓之间的交点
intersection_contours_xld (Contour, ContCircle3, all, Row, Column, IsOverlapping1)
intersection_contours_xld (Contour, ContCircle1, all, Row2, Column2, IsOverlapping3)
intersection_contours_xld (Contour, ContCircle2, all, Row4, Column4, IsOverlapping5)3、获得角平分线三边角平分线交点为圆心
//以交点为圆心画出两个同半径圆两圆交点连线即为角平分线
gen_circle_contour_xld (ContCircle31, Row[0], Column[0], 40, 0, 6.28318, positive, 1)
gen_circle_contour_xld (ContCircle32, Row[1], Column[1], 40, 0, 6.28318, positive, 1)
intersection_contours_xld (ContCircle31, ContCircle32, all, Row1, Column1, IsOverlapping2)
disp_line (3600, Row1[0], Column1[0], Row1[1], Column1[1])gen_circle_contour_xld (ContCircle21, Row2[0], Column2[0], 40, 0, 6.28318, positive, 1)
gen_circle_contour_xld (ContCircle22, Row2[1], Column2[1], 40, 0, 6.28318, positive, 1)
intersection_contours_xld (ContCircle21, ContCircle22, all, Row3, Column3, IsOverlapping4)
disp_line (3600, Row3[0], Column3[0], Row3[1], Column3[1])gen_circle_contour_xld (ContCircle11, Row4[0], Column4[0], 40, 0, 6.28318, positive, 1)
gen_circle_contour_xld (ContCircle12, Row4[1], Column4[1], 40, 0, 6.28318, positive, 1)
intersection_contours_xld (ContCircle11, ContCircle12, all, Row5, Column5, IsOverlapping6)
disp_line (3600, Row5[0], Column5[0], Row5[1], Column5[1])延长直线求交点
r: Row1[0] - Row1[1]
n: Column1[0] - Column1[1]
k1: r/n
b1:Row1[1] - k1*Column1[1]
row1:k1*5b1
row12:k1*2500b1
disp_line (3600, row1, 5, row12, 2500)
r: Row3[0] - Row3[1]
n: Column3[0] - Column3[1]
k1: r/n
b1:Row3[1] - k1*Column3[1]
row2:k1*5b1
row22:k1*2500b1
* disp_line (3600, RowBegin, ColBegin, RowEnd, ColEnd)
disp_line (3600, row2,5 , row22, 2500)
r: Row5[0] - Row5[1]
n: Column5[0]- Column5[1]
k1: r/n
b1:Row5[1] - k1*Column5[1]
row3:k1*5b1
row32:k1*2500b1
disp_line (3600, row3,5 , row32, 2500)//求出圆心 Row6, Column6
intersection_lines (row2, 5, row22, 2500, row3,5 , row32, 2500, Row6, Column6, IsOverlapping7)三、求出圆心到边最短距离即半径
distance_pc(Contour, Row6, Column6, DistanceMin, DistanceMax)
gen_circle_contour_xld (ContCircle, Row6, Column6, DistanceMin, 0, 6.28318, positive, 1)
